提交时间:2019-10-08 20:09:47
运行 ID: 1411
#include<iostream> int main(){ int a,n,b,c,d; scanf("%d",&n); a=n/3600; b=(n-a*3600)/60; c=n-a*3600-b*60; printf("%d:%d:%d",a,b,c); return 0; }