提交时间:2019-11-25 18:59:02
运行 ID: 2432
#include<iostream> using namespace std; int main(){ int num,l,m; double n[100]={0}; double sum=0; double s; cin>>num; for(int i=0;i<num;i++){ cin>>n[i]; sum+=n[i]; s=sum/num; if(n[i]>s) l=n[i]; m=i; } printf("%.1lf\n%d:%d",s,m,l); return 0; }