提交时间:2019-11-26 21:00:55

运行 ID: 2471

#include<iostream> using namespace std; int main(){ int a[100],n,j=0; float sum=0,ave; cin>>n; for(int i=1;i<=n;i++){ cin>>a[i]; sum+=a[i]; } ave=sum/n; printf("%.1f\n",ave); for(int i=1;i<=n;i++) if(a[i]>ave) cout<<i<<":"<<a[i]<<" "; return 0; }